3x^2-20=-x

Solution for 3x^2-20=-x equation:

3x^2-20=-x

We move all terms to the left:

3x^2-20-(-x)=0

We add all the numbers together, and all the variables

3x^2-(-1x)-20=0

We get rid of parentheses

3x^2+1x-20=0

We add all the numbers together, and all the variables

3x^2+x-20=0

a = 3; b = 1; c = -20;
Δ = b2-4ac
Δ = 12-4·3·(-20)
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{241}}{2*3}=\frac{-1-\sqrt{241}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{241}}{2*3}=\frac{-1+\sqrt{241}}{6}
$